Seqio.Parse Some Error
I am a beginner in bioinformatics world. I am following exercise on biopython but i am stuck here.
I am not sure why print command is not working. Please let me know to correct this step.
> from Bio import SeqIO
> for seq_record in SeqIO.parse(" /Documents/biopython/hsa_piwil3.fasta", "fasta"):
... print seq_record.id
File "<stdin>", line 2
print seq_record.id
^
IndentationError: expected an indented block
>
thank you in advance
• 2.3k views
You’ll want to read the python section on indentation, as it’s very important in python. Something like the following will likely work:
from Bio import SeqIO
for seq_record in SeqIO.parse(" /Documents/biopython/hsa_piwil3.fasta", "fasta") :
print seq_record.id
Indentation means the space from margin to the begin of characters in a line. Python language is a very sensitive language for indentation, it has caused confusion for many beginners. Putting in an extra space or leaving one out where it is needed will surely generate an error message . Some common causes of this error include:
- Forgetting to indent the statements within a compound statement.
- Forgetting to indent the statements of a user-defined function.
The error message IndentationError: expected an indented block would seem to indicate that you have an indentation error. It is probably caused by a mix of tabs and spaces .
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